SpringMVC結合Ajaxfileupload異步多文件上傳至遠程服務器
項目中我們可能會使用到異步上傳并且有時需要是異步的，那么Ajaxfileupload是一個不錯的選擇,最近剛 做了一個多文件上傳到遠程服務器，遠程服務器提供接口，當遠程服務器上傳結束后返回一個文件的服務器地址。分享出來給有需要的參考 下，Ajaxfileupload默認是一次只能上傳一個文件的，所以需要稍稍修改下他的源碼就可以上傳多個文件，這里就不多說，百度一下自然就知道。
<input type="file" id="playeraddress" name="playeraddress" /> <input type="file" id="cover" name="cover" /> //這里就是兩個file id自己定義
$.ajaxFileUpload({
url : web_path+'upload/upload.do',
secureuri : false,
data : data,//需要傳遞的數據 json格式
fileElementId :['playeraddress','cover'],
dataType : 'json',
success : function(data) {
//上傳成功后的回調。
},
error : function(data) {
}
});
/*
@param request
@param response
@param audioItem
@return
/
@RequestMapping(value = "/upload.do", method = { RequestMethod.POST })
@ResponseBody
public String addMusic(HttpServletRequest request,
HttpServletResponse response, AudioItem audioItem) {
//這里無需理會，這只是
String uploadFileUrl = GlobalUtil .getValue("upload_audioItem_audio_url");
String uploadIconUrl = GlobalUtil.getValue("upload_audioItem_pic_url");
CommonsMultipartResolver resolver = new CommonsMultipartResolver(
request.getServletContext());
if (resolver.isMultipart(request)) {
MultipartHttpServletRequest multiRequest = (MultipartHttpServletRequest) request;
// 取得request中的所有文件名
Iterator<String> iter = multiRequest.getFileNames();
while (iter.hasNext()) {
String fileName = iter.next();
// 取得上傳文件
MultipartFile file = multiRequest.getFile(fileName);
/*
獲取文件名
*/
String originalFilename = file.getOriginalFilename();
if ("playeraddress".equals(fileName)&&!"".equals(originalFilename)) {
try {
//這里的upload方法就是以http post的方式上傳文件的 稍后貼出
String url = BaseService.upload(uploadFileUrl,
file.getOriginalFilename(),
file.getInputStream());
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
if ("cover".equals(fileName)&&!"".equals(originalFilename)){
try {
String icon = BaseService.upload(uploadIconUrl,
file.getOriginalFilename(),
file.getInputStream());
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
//這里需要注意 使用Ajaxfileupload需要使用以下方式返回結果 回調不了success 方法
response.setContentType("text/html");
try {
response.getWriter().write("ok");
} catch (IOException e) {
e.printStackTrace();
}
}
return null;
}</pre>
//最后一步了
public static String upload(String httpurl, String fileName, InputStream inputStream) {
String result = "";
try {
//這里看你的網絡環境 按需設置代理 正常都不需要理會
if (true) {
System.setProperty("http.proxyHost", BaseService.PROXY_IP);
System.setProperty("http.proxyPort", BaseService.PROXY_PORT);
}
String BOUNDARY = "---------7d4a6d158c9"; // 定義數據分隔線
URL url = new URL(httpurl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
// 發送POST請求必須設置如下兩行
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setUseCaches(false);
conn.setRequestMethod("POST");
conn.setRequestProperty("connection", "Keep-Alive");
conn.setRequestProperty("user-agent",
"Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1)");
conn.setRequestProperty("Charsert", "UTF-8");
conn.setRequestProperty("Content-Type",
"multipart/form-data; boundary=" + BOUNDARY);
OutputStream out = new DataOutputStream(conn.getOutputStream());
byte[] end_data = ("\r\n--" + BOUNDARY + "--\r\n").getBytes();// 定義最后數據分隔線
StringBuilder sb = new StringBuilder();
sb.append("--");
sb.append(BOUNDARY);
sb.append("\r\n");
sb.append("Content-Disposition: form-data;name=\"file" + 1
+ "\";filename=\"" + fileName + "\"\r\n");
sb.append("Content-Type:application/octet-stream\r\n\r\n");
byte[] data = sb.toString().getBytes();
out.write(data);
DataInputStream in = new DataInputStream(inputStream);
int bytes = 0;
byte[] bufferOut = new byte[1024];
while ((bytes = in.read(bufferOut)) != -1) {
out.write(bufferOut, 0, bytes);
}
out.write("\r\n".getBytes()); // 多個文件時，二個文件之間加入這個
in.close();
out.write(end_data);
out.flush();
out.close();
// 定義BufferedReader輸入流來讀取URL的響應
BufferedReader reader = new BufferedReader(new InputStreamReader(
conn.getInputStream()));
String line = null;
while ((line = reader.readLine()) != null) {
result+=line;
}
} catch (Exception e) {
System.out.println("發送POST請求出現異常！" + e);
}
return new JSONObject(result).getString("url");
}
// 到這就結束了！希望能幫到你。</pre>
來自：http://my.oschina.net/pingdy/blog/361833