雙向鏈表實現java代碼
一個LinkedList的實現,非java util 的實現,沒有用java util容器,純實現過程,主要看算法。
/*
* To change this template, choose Tools | Templates
* and open the template in the editor.
*/
package linkedlisttest;
/**
*
* @author Lindily
*/
public class LinkedList<E> {
int size = 0;
Node<E> head = new Node(null, null, null);
public LinkedList() {
head.next = head.previous = head;
}
public void add(E node) {
//核心 循環雙向鏈表
Node<E> newNode = new Node(head.previous, node, head); //新節點的prev指向頭結點的prev 新節點的next指向頭結點
newNode.previous.next = newNode; //調整,新節點的前一個的后一個
newNode.next.previous = newNode; //調整,新節點的后一個的前一個
size++;
}
public Node get(int index) {
if (index < 0 || index >= size) {
throw new IndexOutOfBoundsException("Index:" + index + ",size:" + size);
}
Node node = head;
if (index < (size >> 1)) { //index轉為二進制帶符號向右移動一個bit,相當于index/2
for (int i = 0; i <= index; i++) { //head是啞元,i<=index當index=0時,返回head.next
node = node.next; //對頭結點進行迭代
}
}else{
for(int i=size;i>index;i--){
node=node.previous;
}
}
return node;
}
public int size() {
return size;
}
public static void main(String[] args) {
LinkedList list = new LinkedList();
list.add(1);
list.add(2);
list.add(3);
for (int i = 0; i < list.size; i++) {
System.out.println(list.get(i).node);
}
}
}
class Node<E> {
E node;
Node<E> next;
Node<E> previous;
public Node(Node<E> previous, E node, Node<E> next) {
this.node = node;
this.next = next;
this.previous = previous;
}
}
/*
* To change this template, choose Tools | Templates
* and open the template in the editor.
*/
package linkedlisttest;
/**
*
* @author Lindily
*/
public class SingleLinkedList<T> {
int size = 0;
Node<T> head, tail;
public SingleLinkedList() {
head = tail = null;
}
public void add(T node) {
if (size == 0) {
head = tail = new Node<T>(node, null);
} else {
tail.next = new Node<T>(node, null);
tail = tail.next;
}
size++;
}
public Node<T> get(int index) {
if (index < 0 || index >= size) {
throw new IndexOutOfBoundsException("Index:" + index + ",size:" + size);
}
Node<T> node = head;
for (int i = 0; i < index; i++) { //當index=0時,i不小于index(零不小于零),于是直接return頭結點,與linkedList不同,head不是啞元
node = node.next; //對頭結點進行迭代
}
return node;
}
public int size(){
return size;
}
public static void main(String[] args){
SingleLinkedList list=new SingleLinkedList();
list.add(1);
list.add(2);
list.add(3);
for(int i=0;i<list.size();i++){
System.out.println(list.get(i).node);
}
}
}
class Node<T> {
T node;
Node<T> next;
public Node(T node, Node next) {
this.node = node;
this.next = next;
}
}
本文由用戶 nbnb 自行上傳分享,僅供網友學習交流。所有權歸原作者,若您的權利被侵害,請聯系管理員。
轉載本站原創文章,請注明出處,并保留原始鏈接、圖片水印。
本站是一個以用戶分享為主的開源技術平臺,歡迎各類分享!