本代碼可以幫你自動剪切掉圖片的邊緣空白區域，如果你的圖片有大片空白區域（只要是同一顏色形成一定的面積就認為是空白區域），下面的python代碼可以幫你自動切除，如果是透明圖像，會自動剪切大片的透明部分。
本代碼需要PIL模塊

import Image, ImageChops

def autoCrop(image,backgroundColor=None):
    '''Intelligent automatic image cropping.
       This functions removes the usless "white" space around an image.

   If the image has an alpha (tranparency) channel, it will be used
   to choose what to crop.

   Otherwise, this function will try to find the most popular color
   on the edges of the image and consider this color "whitespace".
   (You can override this color with the backgroundColor parameter) 

   Input:
        image (a PIL Image object): The image to crop.
        backgroundColor (3 integers tuple): eg. (0,0,255)
             The color to consider "background to crop".
             If the image is transparent, this parameters will be ignored.
             If the image is not transparent and this parameter is not
             provided, it will be automatically calculated.

   Output:
        a PIL Image object : The cropped image.
'''

def mostPopularEdgeColor(image):
    ''' Compute who's the most popular color on the edges of an image.
        (left,right,top,bottom)

        Input:
            image: a PIL Image object

        Ouput:
            The most popular color (A tuple of integers (R,G,B))
    '''
    im = image
    if im.mode != 'RGB':
        im = image.convert("RGB")

    # Get pixels from the edges of the image:
    width,height = im.size
    left   = im.crop((0,1,1,height-1))
    right  = im.crop((width-1,1,width,height-1))
    top    = im.crop((0,0,width,1))
    bottom = im.crop((0,height-1,width,height))
    pixels = left.tostring() + right.tostring() + top.tostring() + bottom.tostring()

    # Compute who's the most popular RGB triplet
    counts = {}
    for i in range(0,len(pixels),3):
        RGB = pixels[i]+pixels[i+1]+pixels[i+2]
        if RGB in counts:
            counts[RGB] += 1
        else:
            counts[RGB] = 1   

    # Get the colour which is the most popular:       
    mostPopularColor = sorted([(count,rgba) for (rgba,count) in counts.items()],reverse=True)[0][1]
    return ord(mostPopularColor[0]),ord(mostPopularColor[1]),ord(mostPopularColor[2])

bbox = None

# If the image has an alpha (tranparency) layer, we use it to crop the image.
# Otherwise, we look at the pixels around the image (top, left, bottom and right)
# and use the most used color as the color to crop.

# --- For transparent images -----------------------------------------------
if 'A' in image.getbands(): # If the image has a transparency layer, use it.
    # This works for all modes which have transparency layer
    bbox = image.split()[list(image.getbands()).index('A')].getbbox()
# --- For non-transparent images -------------------------------------------
elif image.mode=='RGB':
    if not backgroundColor:
        backgroundColor = mostPopularEdgeColor(image)
    # Crop a non-transparent image.
    # .getbbox() always crops the black color.
    # So we need to substract the "background" color from our image.
    bg = Image.new("RGB", image.size, backgroundColor)
    diff = ImageChops.difference(image, bg)  # Substract background color from image
    bbox = diff.getbbox()  # Try to find the real bounding box of the image.
else:
    raise NotImplementedError, "Sorry, this function is not implemented yet for images in mode '%s'." % image.mode

if bbox:
    image = image.crop(bbox)

return image




范例：裁剪透明圖片:
im = Image.open('myTransparentImage.png')
cropped = autoCrop(im)
cropped.show()
范例：裁剪非透明圖片
im = Image.open('myImage.png')
cropped = autoCrop(im)
cropped.show()</pre>