python中的字典用法示例
#!/usr/bin/env python #[SNIPPET_NAME: Dictionaries 101]
[SNIPPET_CATEGORIES: Python Core]
[SNIPPET_DESCRIPTION: Basic and not so basic dictionary operations]
[SNIPPET_AUTHOR: Bruno Girin <brunogirin@gmail.com>]
[SNIPPET_LICENSE: GPL]
This snippet demonstrates how the basics on dictionaries: how to create, add,
remove items, get items, iterate, etc.
#
First, let's create simple dictionary. A dictionary (called map in Java hash
in perl) is similar to a list with the difference that the key doesn't
have to be an integer, it can be anything.
#
A dictionary is enclosed in curly brackets and each key is mapped to its
corresponding value with a colon. So in the dictionary below, we associate
the key Karmic with the value 9.10 and so on for the 5 pairs.
# print "Create a simple dictionary" simpleDict = {"Karmic": "9.10", "Lucid": "10.04", "Hardy": "7.10", "Jaunty": "8.10", "Intrepid": "8.04"}
print it
print simpleDict #
Another way to create a dictionary is to zip two lists containing the keys
and values in the same order to create a list of tuples, which we can then
pass to the dict() method to create a dictionary.
# myKeys = ['Feisty', 'Edgy', 'Dapper'] myValues = ['7.04', '6.10', '6.06'] otherDict = dict(zip(myKeys, myValues)) print otherDict #
Interrogate the dictionary. It works exactly the same as with a list, with the
exception that the key is no longer an integer.
# print "\nInterrogate the dictionary"
get for value for key Jaunty
print simpleDict['Jaunty']
get the length of the dictionary
print len(simpleDict)
check if the dictionary contains the key Lucid
print 'Lucid' in simpleDict print 'Breezy' in simpleDict #
Modify the dictionary
# print "\nModify the dictionary"
add another item
simpleDict['Hoary'] = '5.06' print simpleDict
oops! let's sort this out by replacing in place
simpleDict['Hoary'] = '5.04' print simpleDict
update the dictionary with mappings from another one
simpleDict.update(otherDict) print simpleDict
remove an item from the list (Hardy should not be in the list anymore)
del simpleDict['Hoary'] print simpleDict #
Iterate over the dictionary. A dictionary doesn't enforce a natural ordering
like a list but we can still iterate over it in multiple ways.
However, note that when you iterate, the order in which the items are
retrieved is unspecified.
# print "\nIterate over the dictionary" print "\nby keys" for k in simpleDict.keys(): print k print "\nby values" for v in simpleDict.values(): print v print "\nby items"
note the syntax to retrieve the key and value at the same time
for k, v in simpleDict.items(): print k, '=>', v #
More interesting transformations from list to dictionary and vice versa.
List comprehension allow you to do a lot of interesting stuff, in particular
tranforming lists into dictionaries and the other way around.
# print "\nList to dictionary and vice versa"
First, let's transform our dictinary into a list of tuples
simpleList = [(k, v) for k, v in simpleDict.items() ] print simpleList
Create a map from a list with the list's entry as key and the index as value
This method takes advantage of another way of creating a map, using a
sequence of tuples, so in practice, we create a tuple for each item in the
list, create a list from all the tuples using a list comprehension and pass
it as argument to the dict() function
cityList = ['London', 'Paris', 'New York', 'Tokyo'] cityDict = dict([(x, i) for i, x in enumerate(cityList)]) print cityDict
Create a map from a number to its square
squareDict = dict([(x, x * x) for x in range(1, 10)]) print squareDict</pre>