PHP 調用 MySQL 存儲過程并獲得返回值

<h1>Employee listing</h1>
<form method="post" >
<p>Enter Department ID:
<input type="text" name="dept_id" size="4">
<input type="submit" name="submit" value="submit"><p>
</form>

<?php
$hostname = "localhost";
$username = "root";
$password = "secret";
$database = "prod";
if (IsSet ($_POST['submit'])) {

 $dbh = new mysqli($hostname, $username, $password, $database);

 /* check connection */
 if (mysqli_connect_errno()) {
      printf("Connect failed: %s\n", mysqli_connect_error());
      exit ();
 }
 $dept_id = $_POST['dept_id'];

 if ($result_set = $dbh->query("call employee_list( $dept_id )")) {
      print ('<table border="1" width="30%"> <tr> '.
           '<td>Employee_id</td><td>Surname</td><td>Firstname</td></tr>');
      while ($row = $result_set->fetch_object()) {
           printf("<tr><td>%s</td><td>%s</td><td>%s</td></tr>\n",
                  $row->employee_id, $row->surname, $row->firstname);
      }
 } else {
      printf("<p>Error:%d (%s) %s\n", mysqli_errno($dbh),
             mysqli_sqlstate($dbh), mysqli_error($dbh));
 }
 print ("</table> ");
 $dbh->close();

}
?></pre>