C#取兩個時間的時間差并去除周末
C#取兩個時間的時間差并去除周末,取時間差的代碼很多,但是能夠只取工作日的時間差的代碼很少
protected void Page_Load(object sender, EventArgs e)
{
DateTime start = Convert.ToDateTime("2012-12-10");
DateTime end= Convert.ToDateTime("2012-12-18");
TimeSpan span = end - start;
//int totleDay=span.Days;
//DateTime spanNu = DateTime.Now.Subtract(span);
int AllDays=Convert.ToInt32(span.TotalDays)+1;//差距的所有天數
int totleWeek = AllDays / 7;//差別多少周
int yuDay = AllDays % 7; //除了整個星期的天數
int lastDay = 0;
if (yuDay == 0) //正好整個周
{
lastDay = AllDays - (totleWeek * 2);
}
else
{
int weekDay = 0;
int endWeekDay = 0; //多余的天數有幾天是周六或者周日
switch (start.DayOfWeek)
{
case DayOfWeek.Monday:
weekDay = 1;
break;
case DayOfWeek.Tuesday:
weekDay = 2;
break;
case DayOfWeek.Wednesday:
weekDay = 3;
break;
case DayOfWeek.Thursday:
weekDay = 4;
break;
case DayOfWeek.Friday:
weekDay = 5;
break;
case DayOfWeek.Saturday:
weekDay = 6;
break;
case DayOfWeek.Sunday:
weekDay = 7;
break;
}
if ((weekDay == 6 && yuDay >= 2) || (weekDay == 7 && yuDay >= 1) || (weekDay == 5 && yuDay >= 3) || (weekDay == 4 && yuDay >= 4) || (weekDay == 3 && yuDay >= 5) || (weekDay == 2 && yuDay >= 6) || (weekDay == 1 && yuDay >=7))
{
endWeekDay =2;
}
if ((weekDay == 6 && yuDay < 1) || (weekDay == 7 && yuDay <5) || (weekDay == 5 && yuDay < 2) || (weekDay == 4 && yuDay < 3) || (weekDay == 3 && yuDay < 4) || (weekDay == 2 && yuDay < 5) || (weekDay == 1 && yuDay < 6)) {
endWeekDay = 1;
}
lastDay = AllDays - (totleWeek * 2) - endWeekDay;
}
lblTime.Text = lastDay.ToString();
}</pre>
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