C++ 實現判斷一個輸入日期是星期幾,是一年中的第幾天
/ 通過輸入年月日,計算出這一天是星期幾,計算這一天是這一年的多少天,判斷這一年是否為閏年/include<iostream>
using namespace std;
struct time { int year; int month; int day; unsigned int weekday; };
void initialtime(time & t);//輸入初始化時間 void Show(time & t);//顯示時間信息 int Weekdaycount(time & t);//計算當日是星期幾 int Daycount(time & t);//計算當日是第公元多少天 int Daysyearcount(time & t);//計算當日是該年的第多少天 bool isleapyear(time & t);//判斷該年是不是閏年 bool check(time &t);//檢查時間格式是否正確
int main() { time t; initialtime(t); Show(t); return 0; }
bool check(time &t) { if (t.year <= 0 || (t.month <= 0 || t.month>12) || t.day <= 0) return false; else{ if ((t.month == 1 || t.month == 3 || t.month == 5 || t.month == 7 || t.month == 8 || t.month == 10 || t.month == 12) && t.day > 31)return false; else { if ((t.month == 4 || t.month == 6 || t.month == 9 || t.month == 11 ) && t.day > 30)return false; else { if (t.month == 2) { if (isleapyear(t)) { if (t.day > 29)return false; else return true; } else { if (t.day > 28)return false; else return true; } } } } } } void initialtime(time & t) { cout << "Enter the time (year,month,day):\n"; cin >> t.year; cin.get(); cin>> t.month; cin.get(); cin >> t.day; cin.get(); if (!check(t)){ cout << "Try again:\n"; initialtime(t); } else t.weekday = Weekdaycount(t); } void Show(time & t) { cout << "Year: " << t.year << "\t"; cout << "Month: " << t.month << "\t"; cout << "Day: " << t.day << "\t"; cout << "Weekday: " << t.weekday << endl; cout << "This is a "; if (isleapyear(t))cout << "leap"; else cout << "nonleap"; cout << " year.\n"; cout << "Today is the " << Daysyearcount(t) << " days of the year.\n"; } int Weekdaycount(time & t) { return Daycount(t) % 7; } int Daycount(time & t) { int days = 0; days = (t.year - 1) * 365 + (t.year - 1) / 4 - (t.year - 1) / 100
- (t.year - 1) / 400 + Daysyearcount(t);
return days;
}
bool isleapyear(time & t)
{
if (t.year % 4 == 0 && t.year % 100 != 0) return true;//年是四的倍數而且不是100的倍數,是閏年
if (t.year % 400 == 0)return true;
else return false;
}
int Daysyearcount(time & t)
{
int days = 0;
int mtemp = t.month - 1;
while (mtemp > 0)
{
switch (mtemp)
{
case(1) :
case(3) :
case(5) :
case(7) :
case(8) :
case(10) :
case(12) :
days += 31; break;
case(4):
case(6):
case(9):
case(11):
days += 30; break;
case(2) :
days += 28; break;
default:
break;
}
--mtemp;
}
if (isleapyear(t))++days;//如果是閏年,再加上一天
return days+t.day;//返回計算的天數加上當月的天數
}</pre>