用Python實現一個簡單的算術游戲

#!/usr/bin/env python

from operator import add, sub
from random import randint, choice
ops = {'+': add, '-':sub}
定義一個字典
MAXTRIES = 2
def doprob():
    op = choice('+-')

#用choice從'+-'中隨意選擇操作符

    nums = [randint(1,10) for i in range(2)]

#用randint(1,10)隨機生成一個1到10的數,隨機兩次使用range(2)

 nums.sort(reverse=True)

#按升序排序

    ans = opsop

#利用函數

 pr = '%d %s %d = ' % (nums[0], op, nums[1])
    oops = 0

#oops用來計算failure測試,當三次時自動給出答案
while True:
    try:
        if int(raw_input(pr)) == ans:
            print 'correct'
            break
        if oops == MAXTRIES:
            print 'answer\n %s%d' % (pr, ans)
            break
        else:
            print 'incorrect... try again'
            oops += 1
    except (KeyboardInterrupt, EOFError, ValueError):
        print 'invalid ipnut... try again'

def main():
    while True:
        doprob()
        try:
            opt = raw_input('Again? [y]').lower()
            if opt and opt[0] == 'n':
                break
        except (KeyboardInterrupt, EOFError):
            break
if name == 'main':
    main()
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