Ajax實現文件上傳

    <form id="form1" name="form1">            
      <input type="file" name="fileToUpload" id="fileToUpload"  multiple="multiple"/>            
      <progress id="progressBar" value="0" max="100"></progress>            
      <span id="percentage"></span>            
      <input type="button" onclick="UpladFile()" value="Upload" />   
    </form>  

    <script type="text/javascript">

    $(document).ready(function () {

        $('#form1').submit(function () {

        var formdata = new FormData();

        var fileObj = document.getElementById("fileToUpload2").files;

            for (var i = 0; i < fileObj.length; i++)

            formdata.append("file" + i, fileObj[i]);

            $.ajax({

                type: 'POST',

                url: '/Home/Upload2',

                data: formdata,

                /

                                必須false才會自動加上正確的Content-Type                   
                 /

                contentType: false,

                /


            * 必須false才會避開jQuery對 formdata 的默認處理                   
            * XMLHttpRequest會對 formdata 進行正確的處理                   
            */                  
            processData: false              
        }).then(function () {                   
            alert('done');               
        }, function () {                   
            //failCal               
        });               
        return false;           
    });               
});          
function ajaxUpload() {           
    $("#form1").submit();       
}   
</script>  </pre><br />