Android ListView實現任意layout
SimpleAdapter adapter = new SimpleAdapter(this, getData(),
R.layout.timenotes_item_left, new String[] { "text1", "text2",
"text3" }, new int[] { R.id.textView2, R.id.textView3,
R.id.textView4 }) {
@Override
public View getView(int position, View convertView, ViewGroup parent) {
Map itemData = (Map) getItem(position);
int type = Integer.parseInt(itemData.get("type").toString());
View itemView = null;
switch (type) {
case 0:
Log.d("adapter", "type 0");
itemView = View.inflate(getApplicationContext(),
R.layout.timenotes_item_left, null);
break;
case 1:
Log.d("adapter", "type 1");
itemView = View.inflate(getApplicationContext(),
R.layout.timenotes_item_right, null);
break;
default:
Log.d("adapter", "type default");
break;
}
return itemView;
}
};
ListView listView = (ListView) findViewById(R.id.listView1);
listView.setAdapter(adapter); 本文由用戶 jopen 自行上傳分享,僅供網友學習交流。所有權歸原作者,若您的權利被侵害,請聯系管理員。
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